markdown
Basic Exercises on Local Linear Approximationmd eeed9c7
exercise/math/calculus/local-linear-approximation-and-differentiability.exercise.n.md

Basic Exercises on Local Linear Approximation

date2026-07-15document_iddoc_eafa6b353573ea94a0d1c869f22d1f82description局所線型近似、微分可能性、接線近似の誤差の意味を確認する基本演習である。prerequisites局所線型近似と微分可能性type問題演習content_typeexercisestatusactiverelateddata/lecture/math/calculus/local-linear-approximation-and-differentiability.lecture.n.md / data/lecture/math/linear-algebra/linearity-basics.lecture.n.md
mathcalculusexerciselinear-approximation
data/lecture/math/calculus/local-linear-approximation-and-differentiability.lecture.n.md

1Problem 1

Find the local linear approximation of f(x)=x near x=9 and use it to approximate 9.2.

1.1Sample Solution

Let f(x)=x. Rationalizing the difference quotient gives

9+h-3h=19+h+3(h0,9+h>0),

so f(9)=1/6. Since f(9)=3, the local linear approximation is

f(x)3+16(x-9).

Therefore,

9.23+0.26=3.0333_.

1.2Explanation

The approximation has the same value and slope as the function at the base point x=9. The actual value is 9.23.03315, confirming that the approximation error is small.

1.3Common Error

The approximation need not retain the same accuracy far from the base point. The word local indicates that the approximation is valid in a neighborhood of that point.


2Problem 2

Find the tangent line to f(x)=x2 at x=1.

2.1Sample Solution

For f(x)=x2, f(1)=1, and the difference quotient is

(1+h)2-1h=2+h(h0).

Thus f(1)=2, and the tangent line is

y=1+2(x-1).

2.2Explanation

For the increment h=x-1, the linear map is L(h)=2h. The tangent line y=1+2h is the affine approximation obtained by adding the constant term.


3Problem 3

Let f(x)=x2 and fix an arbitrary base point aR. Find the remainder r(h) satisfying

f(a+h)=f(a)+f(a)h+r(h),

and verify that r(h)=o(h).

3.1Sample Solution

Since f(a)=2a,

(a+h)2=a2+2ah+h2,

so r(h)=h2. Moreover,

r(h)h=h0(h0).

Therefore, r(h)=o(h).

3.2Explanation

The first-order term 2ah forms the linear part acting on the increment, while the second-order term h2 is negligible relative to |h|. Thus the complete affine approximation is a2+2ah. This calculation illustrates the equivalence between differentiability defined by difference quotients and its characterization using an o(h) remainder.

4Related Material

data/lecture/math/calculus/local-linear-approximation-and-differentiability.lecture.n.md
raw .n.md をコピー
loc をコピー (filepath:line ~ line)
copy share link
copy encoded share link
path をコピー
copy share link
copy encoded share link
copy share link
copy encoded share link
タブを全て閉じる