Basic Exercises on Local Linear Approximation
1Problem 1
Find the local linear approximation of near and use it to approximate .
1.1Sample Solution
Let . Rationalizing the difference quotient gives
so . Since , the local linear approximation is
Therefore,
1.2Explanation
The approximation has the same value and slope as the function at the base point . The actual value is , confirming that the approximation error is small.
1.3Common Error
The approximation need not retain the same accuracy far from the base point. The word local indicates that the approximation is valid in a neighborhood of that point.
2Problem 2
Find the tangent line to at .
2.1Sample Solution
For , , and the difference quotient is
Thus , and the tangent line is
2.2Explanation
For the increment , the linear map is . The tangent line is the affine approximation obtained by adding the constant term.
3Problem 3
Let and fix an arbitrary base point . Find the remainder satisfying
and verify that .
3.1Sample Solution
Since ,
so . Moreover,
Therefore, .
3.2Explanation
The first-order term forms the linear part acting on the increment, while the second-order term is negligible relative to . Thus the complete affine approximation is . This calculation illustrates the equivalence between differentiability defined by difference quotients and its characterization using an remainder.