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lecture/math/differential-equations/exact-differential-equations.lecture.n.md
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Exact Differential Equations

date2026-07-16document_iddoc_19e374567611bbdcb63bdd3695c4eaf9description完全微分方程式を、ポテンシャル関数 F(x,y) の全微分を復元する問題として導入し、完全性条件と積分因子の意味を証明付きで整理する。prerequisites一階微分方程式の分類と最初の判定 / 一階線型微分方程式と積分因子 / 多変数関数と偏微分type講義content_typelecturestatusactiverelateddata/lecture/math/differential-equations/classifying-first-order-odes.lecture.n.md / data/lecture/math/differential-equations/first-order-linear-odes-and-integrating-factors.lecture.n.md / data/lecture/math/differential-equations/homogeneous-first-order-odes-and-substitution.lecture.n.md / data/lecture/math/multivariable-calculus/multivariable-functions-and-partial-derivatives.lecture.n.md / data/lecture/math/vector-calculus/line-integrals-and-conservative-fields.lecture.n.md / data/exercise/math/differential-equations/classifying-and-solving-first-order-odes.exercise.n.md
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1Introduction

This lecture explains how to reconstruct the differential form

M(x,y)dx+N(x,y)dy

as the total differential of a function F(x,y):

dF=Fxdx+Fydy.

Separation of variables divides an equation into an x-dependent side and a y-dependent side. The integrating-factor method for first-order linear equations converts the left-hand side into the derivative of a product. Exact differential equations instead represent the entire left-hand side as the total differential of one function F(x,y).

2Standard Form

An exact differential equation is an equation

M(x,y)dx+N(x,y)dy=0

for which there exists a function F(x,y) satisfying

Fx=M,Fy=N.

The function F is called a potential function.

3Proposition 1: Solutions of an Exact Equation Have the Form F(x,y)=C

Suppose that Mdx+Ndy=dF. Then the solutions of

M(x,y)dx+N(x,y)dy=0

are represented implicitly by

F(x,y)=C.

3.1Proof

Since Mdx+Ndy=dF, the equation is dF=0. Along a differentiable curve y=y(x), the chain rule gives

ddxF(x,y(x))=Fx+Fyy.

Substitution of dy=ydx into

dF=Fxdx+Fydy

gives

dF=(Fx+Fyy)dx.

Thus dF=0 implies

ddxF(x,y(x))=0.

Consequently, F is constant along each solution curve, so F(x,y)=C. Conversely, differentiation of F(x,y)=C gives dF=0 and therefore recovers the original equation.

4Exactness Condition

If M and N are continuously differentiable and Fx=M and Fy=N, then the mixed partial derivatives of F are continuous, so

Fxy=Fyx.

Therefore,

My=Nx

is necessary for exactness.

If M and N are continuously differentiable and the domain is simply connected, then

My=Nx

is also sufficient for exactness. A simply connected domain is a domain in which every closed curve can be continuously contracted to a point without leaving the domain. Rectangles and disks are standard examples.

5Proposition 2: Necessity of the Exactness Condition

Suppose that M and N are continuously differentiable and that M=Fx and N=Fy. Then

My=Nx.

5.1Proof

Since M=Fx,

My=Fxy.

Since N=Fy,

Nx=Fyx.

Continuity of the mixed partial derivatives gives Fxy=Fyx, and hence

My=Nx.

Thus the exactness condition follows from the interchangeability of the mixed partial derivatives of the potential function.

6Constructing the Potential Function

Once exactness has been established, reconstruct F from Fx=M:

  1. Integrate Fx=M with respect to x.
  2. Add an arbitrary function h(y), because integration with respect to x leaves the y-dependent part undetermined.
  3. Compare Fy with N to determine h(y).

The term h(y) is necessary because its partial derivative with respect to x is zero.

7Example 1: An Exact Equation

Consider

(2xy+1)dx+x2dy=0.

Here,

M=2xy+1,N=x2.

The exactness condition holds because

My=2x,Nx=2x.

To reconstruct the potential, integrate

Fx=2xy+1

with respect to x:

F=x2y+x+h(y).

Differentiation with respect to y gives

Fy=x2+h(y).

Comparison with N=x2 yields

h(y)=0.

Thus h is constant, and the solution is

x2y+x=C.

8When an Integrating Factor Is Required

Even when

Mdx+Ndy=0

is not exact, multiplication by a function μ(x,y) that is nonzero everywhere on the domain may produce the exact equation

μMdx+μNdy=0.

Such a function μ is also called an integrating factor. Because μ is nonzero everywhere, the equations before and after multiplication represent the same solution curves.

For a first-order linear equation, an integrating factor converts the left-hand side into the product derivative

(μy).

For a differential form, an integrating factor converts Mdx+Ndy into a total differential

dF.

Both uses transform an equation into a directly integrable differential.

9Connection with First-Order Linear Equations

Rewrite

y+p(x)y=q(x)

as

(p(x)y-q(x))dx+dy=0.

Then

M=p(x)y-q(x),N=1.

In general,

My=p(x),Nx=0,

so the form is not exact. Multiplication by the linear integrating factor

μ(x)=ep(x)dx

gives

μ(p(x)y-q(x))dx+μdy=0.

For the transformed form,

(μ(py-q))y=μp,(μ)x=μ=μp,

so it is exact. Hence the integrating factor for a first-order linear equation is also an exactness-producing factor in the framework of differential forms.

data/lecture/math/differential-equations/first-order-linear-odes-and-integrating-factors.lecture.n.md

10Scope

The sufficiency of My=Nx depends on the domain. On a domain that is not simply connected, this equality may hold even though no global potential function exists.

This topological qualification reappears in the study of line integrals and conservative vector fields.

data/lecture/math/vector-calculus/line-integrals-and-conservative-fields.lecture.n.md

The next lecture treats equations whose right-hand side depends only on the ratio y/x and explains how the substitution v=y/x reduces them to separable equations.

data/lecture/math/differential-equations/homogeneous-first-order-odes-and-substitution.lecture.n.md

11Exercises

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